Question

3.80 gm of metal M is deposited at the cathode by passing 0.2 F of electricity through the solution of metal chlorides. The formula of the metal chloride is:
(atomic mass of M = 57 g/mol)

• A. $MCl$
• B. $MC{l}_2$
• C. $MC{l}_3$
• D. $MC{l}_4$

Answer 1

The correct option is C $MC{l}_3$

Equivalent mass of metal = $\frac{3.80}{0.2}=19$
$\therefore 19=\frac{57}{n}\Rightarrow n=3$ (n=valency).
Thus formula of the metal chloride will be $MC{l}_3$.