Evaluate: −3(a+b)+4(2a−3b)−(2a−b)
We have, −3(a+b)+4(2a−3b)−(2a−b)
=−3a−3b+8a−12b−2a+b
=−3a+8a−2a−3b−12b+b
=8a−5a−15b+b
=3a−14b