Question

$3A$
$+\underset{–}{25}$
$\underset{–}{B2}$

• A. $A=7,B=8$
• B. $A=2,B=5$
• C. $A=2,B=6$
• D. $A=7,B=6$

Answer 1

Answer: (D)

$A=7,B=6$

There are two letters whose values are to be found out. Study the addition
in the one's column, i.e., from $A+5$ we get $2$, i.e., the number whose ones digit is 2. For this to happen, A must be 7
$(\because A+5=7+5=12)$.
So for the addition in the tens column, we have
$1+3+2=B\Rightarrow B=6$
So, the puzzle has been decoded as
$37$
$\underset{–}{+25}$
$\underset{–}{62}$
$\therefore$ The possible values of $A$ and $B$ are $7$ and $6$ respectively.