Let the cost of a chair be x.
Let the cost of a table be y.
Given that 3 chairs and 2 tables cost 700 rupees
3x + 2y = 700 ------ (1)
Given that 5 chairs and 3 tables cost 1100 rupees.
5x + 3y = 1100 ------ (2)
On solving (1)*3 and (2)*2, we get
10x + 6y = 2200
9x + 6y = 2100
----------------------
x = 100.
Substitute x = 100 in (1), we get
3x + 2y = 700
3(100) + 2y = 700
300 + 2y = 700
2y = 700 - 300
2y = 400
y = 400/2
y = 200.
Therefore the cost of 2 chairs = 2 * 100
= 200 rupees.
Therefore the cost of 2 tables = 2 * 200
= 400 rupees.
Verification:
3x + 2y = 700
3(100) + 2(200) = 700
300 + 400 = 700
700 = 700.
5x + 3y = 1100
5(100) + 3(200) = 1100
500 + 600 = 1100
1100 = 1100.
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