The correct option is
C Rs.600We take the cost of one chair =Rs.x and that of a table =Rs.yThen, in the first case, total cost =3x+2y and in the second case, total cost =5x+3y.
Also, the cost of 2 chairs+the cost of 2 tables =2x+2y.
So, by the given the given conditions,
3x+2y=700 ...........(i) &
5x+3y=1100 ..........(ii).
(i)×5⟶15x+10y=3500 ......(iii)
(ii)×3⟶15x+9y=3300 .........(iv).
(iii)−(iv)⟶y=200
Substituting y=200 in (i),
3x+2×200=700⟹3x=300⟹x=100
So, the cost of 2 chairs+the cost of 2 tables =2x+2y
=2(x+y)=Rs.2(100+200)=Rs.600