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Question

3 containers having capacities in the ratio 2 : 3 : 1 contain mixture of liquids A and B such that the ratio of A to B in them is 2 : 3, 1 : 4 and 3 : 7 respectively. If all the three containers are emptied in a single container, what will be the ratio of A to B in the final mixture?

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Solution

2+3=5, 1+4=5, 3+7=10
LCM (5,5,10)=0
Capacities are in the ration 2:3:1
Suppose the capacities are 20,30 and 10.
So A in final mixture =
25×20+15×30+310×10
=8+6+3=17
And B in final mixture = (20+30+10)-17
= 43
So, final ratio = 17:43

1240684_1505991_ans_220f24536ccf401e887c61f9ae99fa91.PNG

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