Question

3 containers having capacities in the ratio 2 : 3 : 1 contain mixture of liquids A and B such that the ratio of A to B in them is 2 : 3, 1 : 4 and 3 : 7 respectively. If all the three containers are emptied in a single container, what will be the ratio of A to B in the final mixture?

Answer 1

2+3=5, 1+4=5, 3+7=10

LCM (5,5,10)=0

Capacities are in the ration 2:3:1

Suppose the capacities are 20,30 and 10.

So A in final mixture =

$\frac{2}{5}\times 20+\frac{1}{5}\times 30+\frac{3}{10}\times 10$

=8+6+3=17

And B in final mixture = (20+30+10)-17

= 43

So, final ratio = 17:43