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Byju's Answer
Standard VI
Mathematics
Addition of Fractions
[3 1 / 4 ÷ 1 ...
Question
[
3
1
4
÷
{
1
1
4
−
1
2
(
2
1
2
−
1
4
−
1
6
)
}
]
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Solution
[
3
1
4
÷
(
1
1
4
−
1
2
(
2
1
2
−
1
4
−
1
6
)
)
]
=
3
1
4
÷
[
5
4
−
1
2
(
5
2
−
1
4
−
1
6
)
]
=
13
4
÷
[
5
4
−
5
4
+
1
8
+
1
12
]
=
13
4
÷
[
1
8
+
1
12
]
=
13
4
÷
5
24
=
13
4
×
24
5
=
78
5
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1
Similar questions
Q.
Simplify :
[
3
1
4
÷
{
1
1
4
−
1
2
(
2
1
2
−
1
4
−
1
6
)
}
]
÷
(
1
2
o
f
4
1
3
)
Q.
Evaluate :
1
2
+
3
1
4
+
1
1
6
2
1
2
+
1
1
6
+
6
1
3
+
1
120
Q.
Find the value of:
(1)
(2)
(3)
(4)
(5)