Question

$3\frac{2}{7}-2\frac{1}{14}-1\frac{1}{14}-1\frac{1}{7}=?+2\frac{1}{13}$

• A. $1\frac{1}{7}$
• B. $1\frac{2}{7}$
• C. $\frac{1}{7}$
• D. $\frac{3}{7}$
• E. $Noneofthese$

Answer 1

The correct option is E $Noneofthese$

Here,
$3\frac{2}{7}-2\frac{1}{14}-1\frac{1}{14}-1\frac{1}{7}-2\frac{1}{13}=?$
Solve the integral part and fractional part separately
$\Rightarrow 3\frac{2}{7}-(2\frac{1}{14}+1\frac{1}{14}+1\frac{1}{7}+2\frac{1}{13})=?\Rightarrow 3\frac{2}{7}-\left\{\right(2+1+1+2)+(\frac{1}{14}+\frac{1}{14}+\frac{1}{7}+\frac{1}{13}\left)\right\}=?\Rightarrow 3\frac{2}{7}-\{6+(\frac{1}{7}+\frac{1}{7}+\frac{1}{13}\left)\right\}=?\Rightarrow 3\frac{2}{7}-\{6+(\frac{2}{7}+\frac{1}{13}\left)\right\}=?\Rightarrow \frac{23}{7}-\{6+\frac{26+7}{91}\}=?\Rightarrow \frac{23}{7}-\left\{\frac{546+33}{91}\right\}=?\Rightarrow ?=\frac{299-579}{91}=\frac{-280}{91}$