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Byju's Answer
Standard XII
Chemistry
Solubility Product
3 g of a hydr...
Question
3
g of a hydrocarbon, on combustion in excess of oxygen, produces
8.8
g of
C
O
2
and
5.4
g of
H
2
O
. The data illustrates the law of:
A
conservation of mass
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B
multiple proportions
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C
constant proportions
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D
none of these
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Solution
The correct option is
B
conservation of mass
Weight of
C
O
2
=
8.8
g
m
Moles of
C
O
2
=
8.8
44
=
0.2
Moles of
C
=
0.2
Wt. of
C
=
0.2
×
12
=
2.4
g
Moles of
H
2
O
=
5.4
18
=
0.3
So, moles of
H
atom
=
0.3
×
2
Wt. of hydrogen
=
0.3
×
2
×
1
=
0.6
Wt. of carbon + hydrogen
=
2.4
+
0.6
=
3
=
Initial wt. of hydrocarbon
Hence, it illustrates the law of conservation of mass.
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