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Question

3 g of a hydrocarbon, on combustion in excess of oxygen, produces 8.8 g of CO2 and 5.4 g of H2O. The data illustrates the law of:

A
conservation of mass
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B
multiple proportions
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C
constant proportions
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D
none of these
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Solution

The correct option is B conservation of mass
Weight of CO2=8.8gm
Moles of CO2=8.844=0.2
Moles of C=0.2
Wt. of C=0.2×12=2.4g
Moles of H2O=5.418=0.3
So, moles of H atom =0.3×2
Wt. of hydrogen =0.3×2×1=0.6
Wt. of carbon + hydrogen =2.4+0.6=3= Initial wt. of hydrocarbon
Hence, it illustrates the law of conservation of mass.

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