3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is:
A
18 mg
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B
36 mg
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C
42 mg
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D
54 mg
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Solution
The correct option is A 18 mg Initial millimoles of CH3COOH=0.06×50 Final millimoles of CH3COOH=0.042×50
The mass of CH3COOH adsorbed per gram of charcoal is, =(0.06−0.042)×50×10−3×60×10−33=18 mg