Question

3 g of activated charcoal was added to 50 ml of acetic acid solution (0.06 M) in a flask. After an hour it was filtered, and the strength of filtrate was found to be 0.042 M. The mass of acetic acid adsorbed per gram of charcoal is:

Answer 1

$\text{Change in molarity when}C{H}_{3}COOH\text{gets adsorbed}=0.06-0.042=0.018$
$\text{Number of millimoles of}C{H}_{3}COOH\text{adsorbed}=0.018\times 50=0.90\text{mmol}$
Mass adsorbed $=0.90\times 60=54\text{mg}$
$(\because \text{Molar mass of}C{H}_{3}COOH=60\text{g/mol})$
$\text{Mass adsorbed per gram}=\frac{54}{3}=18\text{mg}=0.018\text{g}$