Question

$3$ letters are posted in $5$ letters boxes. If all the letters are not posted in the same box, then number of ways of posting is

• A. $120$
• B. $125$
• C. $130$
• D. $124$

Answer 1

Answer: (B)

$125$

According to problem,

$3$ letters are posted $5$ boxes

implies that,

we have a letter and can be posted in any of the $5$ boxes.

Similarly next letter can be posted in 5 ways, and the all other follow same method

implies that

${\left(5\right)}^3$

$=5\times 5\times 5$

Hence, $125$ possible ways for posting in $5$ boxes.