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Question

$$3$$ men and $$4$$ boys can do a piece of work in $$14$$ days, while $$4$$ men and $$6$$ boys can do it in $$10$$ days. How long would it take $$1$$ boy to finish the work?


Solution

$$3M+4B=\dfrac{1}{14}$$ (combined rate) ........ 1

$$4M+6B=\dfrac{1}{10}$$ .............. 2

By $$(1) \times 4-$$  $$(2) \times 3 $$ 

$$B=\dfrac{1}{140}$$ i.e $$1$$ Boy would take $$140$$ days to finish works.


Mathematics

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