$3$ men and $4$ boys can do a piece of work in $14$ days, while $4$ men and $6$ boys can do it in $10$ days. How long would it take $1$ boy to finish the work?

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Solution

$3 M + 4 B = \frac{1}{14}$ (combined rate) ........ 1

$4 M + 6 B = \frac{1}{10}$ .............. 2

By $(1) \times 4 -$ $(2) \times 3$

$B = \frac{1}{140}$ i.e $1$ Boy would take $140$ days to finish works.

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3 men and 4 boys can do a piece of work in 14 days, while 4 men and 6 boys can do it in 10 days. How long would it take 1 boy to finish the work?

3M+4B=114 (combined rate) ........ 14M+6B=110 .............. 2By (1)×4− (2)×3 B=1140 i.e 1 Boy would take 140 days to finish works.

$3$ men and $4$ boys can do a piece of work in $14$ days, while $4$ men and $6$ boys can do it in $10$ days. How long would it take $1$ boy to finish the work?

$3 M + 4 B = \frac{1}{14}$ (combined rate) ........ 1

$4 M + 6 B = \frac{1}{10}$ .............. 2

By $(1) \times 4 -$ $(2) \times 3$

$B = \frac{1}{140}$ i.e $1$ Boy would take $140$ days to finish works.