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Question

3 moles of a gas mixture having 8.3 m3 volume and temperature of 90.5 K is compressed to 1/5th of the initial volume. The change in its adiabatic compressibility, if the gas obeys PV19/13= constant is x×103 Pa1 [R=8.3 J/mol-K and 15γ1=0.905], then x is

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Solution

Bulk modulus B=γP
Compressibility C=1B=1γP
and ΔC=CC
or ΔC=1γ.[1P1P]

We know,
PVγ=P(V5)γ
With, γ=19/13 and P=5γP

ΔC=1γP.[15γ11]=13×0.90519P

ΔC=13×0.905×8.319×3×8.3×90.5=0.0022 Pa1

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