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3 moles of an...

Question

3 moles of an ideal monatomic ga Perform ABCDA cyclic process as shown in the figure. The gas temperatures are $T_{A} = 400 K, T_{B} = 800 K; T_{C} = 2400 K; T_{D} = 1200 K$ . The work done by the gas is (approximately) (R = 8.314)/molc K) ?

10KJ

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20 KJ

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40 KJ

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100 KJ

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Solution

The correct option is C 20 KJ
$Given :$ $T_{A} = 400 K$ , $T_{B} = 800 K$ , $T_{C} = 2400 K$ , $T_{D} = 1200 K$

$Solution :$
$W_{B A} = W_{C D} = 0$ (V= const)
$W_{B C} = 3 R (T_{c} - T_{B})$ P=const
$W_{D A} = 3 R (T_{A} - T_{D})$ P=const
$W = 3 R (T_{A} + T_{c} - T_{B} - T_{D})$ =2400R= 20KJ [Nearly]

$Hence B is the correct option$

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Similar questions

3

A B C D A

T_{A} = 400 K, T_{B} = 800 K, T_{C} = 2400 K

T_{D} = 1200 K

(R = 8.314 J / m o l e K)

T_{A} = 400 K, T_{B} = 800 K, T_{C} = 2400 K, T_{D} = 1200 K .

T_{A} = 600 K, T_{B} = 800 K, T_{C} = 2200 K

T_{D} = 1200 K

A B C D A

3

A, B, C, D

T_{A} = 400 K,

T_{B} = 800 K, T_{C} = 2400 K, T_{D} = 1200 K .

T_{A} = 600 K

T_{B} = 800 K

T_{C} = 2200 K

T_{D} = 1200 K

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