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Question

3 moles of an ideal monoatomic gas perfoms a cycle shown in the figure. The gas temperature at A,B,C,D are TA=400 K, TB=800 K,TC=2400 K,TD=1200 K. Find the work done by the gas.

A
12 kJ
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B
20 kJ
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C
120 kJ
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D
24 kJ
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Solution

The correct option is B 20 kJ
As process AB,CD pass through origin on P vs T graphs, we can say that PTV=Constant.
Hence, Isochoric.
WAB=WCD=0

While process BC,DA are isobaric in nature

WBC=3R(TCTB)
WDA=3R(TATD)
Total work done
WAB+WCD+WBC+WDA=3R(TA+TCTBTD)
=3R(400+24008001200)
=2400 R=20 kJ

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