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Byju's Answer

Standard XII

Chemistry

Internal Energy

3 moles of ga...

Question

3 moles of gas requires 60 cal of heat for $5^{o} C$ rise in temperature at constant volume. Then heat required for 5 moles of the same gas under constant pressure for $100^{o} C$ raise in temperature is

2000

Cal

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4000

Cal

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1000

Cal

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3000

Cal

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Solution

The correct option is D $3000$ Cal
At constant volume, W = 0

So, Q = U = $n C_{v} Δ T$

60 = $3 C_{v} \times 5$

$C_{v} = 4$

$C_{p} = C_{v} + R$

$C_{p} = 4 + 2 = 6$

At constant pressure,
Q = $n C_{p} Δ T$

Q = $5 \times 6 \times 100$

Q = 3000 cal

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Similar questions

3

moles of a gas requires

60 c a l

heat for

5^{o} C

rise of temperature at constant volume, then heat required for

5

moles of same gas under constant pressure for

10^{o} C

rise of temperature is

(R = 2 c a l / m o l e - k)

Q. Specific heat at constant volume of a monoatomic gas is 0.75 cal/g. 1 mole of this gas requires 3 cal of heat to raise the temperature of 1 mole of this gas. The heat required to raise the temperature through 1

^{o}

C of 1-mole gas at constant pressure is:

70 cal

of heat is required to raise the temperature of

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moles of an ideal gas at constant pressure from

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. The amount of heat required to raise the temperature of the same gas through same range of temperature (

30^{\circ} C

35^{\circ} C

) at constant volume is
Given

(γ = 7 / 5)

70 calories of heat are required to raise the temperature of 2 moles of an ideal gas at constant pressure from $30^{\circ} C t o 35^{\circ} C$ . The amount of heat required to raise the temperature of same gas through the same range ( $30^{\circ} C t o 35^{\circ} C$ ) at constant volume (R = 2 cal/mol/K)

140 cal

of heat is required to raise the temperature of

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mole of a diatomic gas at constant pressure from

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at constant volume?

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3 moles of gas requires 60 cal of heat for 5oC rise in temperature at constant volume. Then heat required for 5 moles of the same gas under constant pressure for 100oC raise in temperature is

The correct option is D 3000 CalAt constant volume, W = 0So, Q = U = nCvΔT60 = 3Cv×5Cv=4Cp=Cv+RCp=4+2=6At constant pressure,Q = nCpΔTQ = 5×6×100Q = 3000 cal

3 moles of gas requires 60 cal of heat for $5^{o} C$ rise in temperature at constant volume. Then heat required for 5 moles of the same gas under constant pressure for $100^{o} C$ raise in temperature is

The correct option is D $3000$ Cal
At constant volume, W = 0

So, Q = U = $n C_{v} Δ T$

60 = $3 C_{v} \times 5$

$C_{v} = 4$

$C_{p} = C_{v} + R$

$C_{p} = 4 + 2 = 6$

At constant pressure,
Q = $n C_{p} Δ T$

Q = $5 \times 6 \times 100$

Q = 3000 cal