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Question

$${3}^{\prime} AAA$$ $$TGC$$ $$GCG$$ $$ATA {5}^{\prime}$$ is the sequence of nucleotides on a gene, after transcription, the mRNA formed by it and the sequence of bases in the corresponding binding anticodon will be 


A
5UUU ACG CGC UAU3 and 3AAAUGCGCGAUA5
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B
5UAU CGC GCA UUU3 and 3AUAGCGCGUAAA5
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C
5UUU ACC TUG UAU3 and 3AAAUGGUACAUA5
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D
5UAU GUT CCA UUU3 and 3AUACAUGGUAAA5
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Solution

The correct option is A $${5}^{\prime} UUU$$ $$ACG$$ $$CGC$$ $$UAU {3}^{\prime}$$ and $${3}^{\prime} AAA-UGC-GCG-AUA{5}^{\prime}$$
3′-AAA TGC GCG ATA-5′         Non-coding strand
5'-TTT ACG CGC TAT-3'          Coding strand
5'-UUU ACG CGC UAU-3'        mRNA with codons
3'-AAA UGC CGC AUA-5'         tRNA with anticodons

The template (non-coding or antisense) strand is the sequence of the nucleotides on the gene is used for the construction of the mRNA. This template strand is read from 3'-5' direction. The coding strand will be read from 5'-3' direction. The mRNA which is synthesized is similar to the coding strand, only the thymine is replaced by uracil. The mRNA contains codons and the tRNA will contain anticodons and will have opposite directions.
Thus, the correct answer is option A. 

Biology

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