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Question

3sin2x4cos2x

A
[0,3]
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B
[4,0]
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C
[3,4]
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D
[4,3]
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Solution

The correct option is B [4,3]
Let f(x)=3sin2x4cos2x
=3(sin2x+cos2x)7cos2x
f(x)=37cos2x
max. value of f(x)=3 when, cosx=0
min. value of f(x)=37=4, when, cosx=1
range of f(x)[4,3].

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