3(t-3)=5(3t+1)

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Solution

multiply the term into bracket or open the bracket on both side

3t-33 = 53t+5*1

3t-9= 15t + 5

t containing terms comes together

15t - 3t = -9+5

12t = -4

t= -4/12

t = -1/3

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Similar questions

\frac{3 t - 2}{4} - \frac{2 t + 3}{3} = \frac{2}{3} - t

\frac{3 t + 1}{16} - \frac{2 t - 3}{7} = \frac{t + 3}{8} + \frac{3 t - 1}{14}

\frac{3 t + 1}{16} - \frac{2 t - 3}{7} = \frac{t + 3}{8} + \frac{3 t - 1}{14}

3 (t - 3) = 5 (2 t + 1)

When we divide $3 t^{4} + 5 t^{3} - 7 t^{2} + 2 t + 2$ by $t^{2} + 3 t + 1$ , we get $3 t^{2} - 4 t + 2$ as quotient.

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