$3 t a n^{- 1} a$ is equal to

t a n^{- 1} \frac{3 a + a^{3}}{1 + 3 a^{2}}

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t a n^{- 1} \frac{3 a - a^{3}}{1 + 3 a^{2}}

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t a n^{- 1} \frac{3 a + a^{3}}{1 - 3 a^{2}}

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t a n^{- 1} \frac{3 a - a^{3}}{1 - 3 a^{2}}

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Solution

The correct option is D $t a n^{- 1} \frac{3 a - a^{3}}{1 - 3 a^{2}}$
$3 t a n^{- 1} a$ = $t a n^{- 1} \frac{3 a - a^{3}}{1 - 3 a^{2}}$

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