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Question

3-Phenyl propene on reaction with HBr gives (as a major product):

A
C6H5CH2CH(Br)CH3
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B
C6H5CH(Br)CH2CH3
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C
C6H5CH2CH2CH2Br
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D
C6H5CH(Br)CH=CH2
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Solution

The correct option is B C6H5CH(Br)CH2CH3
According to Markovnikov's rule, the negative part of the unsymmetrical reagent adds to less hydrogenated (more substituted) carbon atom of the double bond.


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