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Question

(3×102)+(2×101)+(9×100) expressed in numeral form is .

A
329
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B
32.9
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C
3290
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D
3.290
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Solution

The correct option is A 329
(3×102)+(2×101)+(9×100)
=(3×100) + (2×10) + (9×1) (a0=1)
=300+20+9
=329

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