Using BODMAS [3×{ ( 5) × ( 4) }] ÷{ 27 + ( 13 4) } =[3×{ 20 }] ÷{ 27 17 } = [60] ÷{ 10} =6 ...

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Byju's Answer

Standard VII

Mathematics

Division of Integers

[3 ×-5 ×-4] ÷...

Question

$[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)} =$ ___

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Solution

Using $B O D M A S$

$[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)}$

$= [3 \times {20}] \div {27 - 17}$

$= [60] \div {10}$

$= 6$

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Solve:

[[5×{(−3)×(−4)}]÷{27 + (−14−3)}][[3×{(−4)×(−5)}]÷{27+(−13−4)}]
+[{27×(−2)}÷(−3−3)] + [{27×(−2)}÷(−3−3)]
+[{(−3)×(−3)×5}÷(−3)]]

[3×[(-5)×(-4)]÷[27+(-13-4)]+[(27×(-2)]÷(-3-3)+[(-3)×(-3)×(-5)÷(-3)

Can you explain clearly

The value of the given expression is ___
$[[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)}]$
$+ [{27 \times (- 2)} \div (- 3 - 3)]$
$+ [{(- 3) \times (- 3) \times 5} \div (- 3)]]$

What is the value of the given expression?
$[[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)}]$
$+ [{27 \times (- 2)} \div (- 3 - 3)]$
$+ [{(- 3) \times (- 3) \times 5} \div (- 3)]]$

What is the value of the given expression?
$[[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)}]$

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[3×{(−5)×(−4)}]÷{27+(−13−4)}= ___

Using BODMAS [3×{(−5)×(−4)}]÷{27+(−13−4)} =[3×{20}]÷{27−17} =[60]÷{10} =6

$[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)} =$ ___

Using $B O D M A S$

$[3 \times {(- 5) \times (- 4)}] \div {27 + (- 13 - 4)}$

$= [3 \times {20}] \div {27 - 17}$

$= [60] \div {10}$

$= 6$