Question

3)What is the molarity of a solution formed by dissolving 25.0 g of potassium hydroxide in enough water to form 500.0 mL of solution? (MMPP)

Answer 1

Moles of KOH in 25g = $$\begin{gathered} \frac{25\text{g}}{56.1{\text{gmol}}^{\text{-1}}}=0.4456\text{mol} \\ \text{Molarity}=\frac{0.\text{4456 mol}}{0.5\text{L}}=\text{0.891 M} \end{gathered}$$