Question

$-3(x+1)>6$, where $x$ is an integer, is an algebraic inequality. The maximum value of $x$ is

Answer 1

Given algebraic inequality : $-3(x+1)>6$

Step 1: Divide both sides of the inequality by $-3$
We know: On dividing or multiplying both sides of an inequality by a negative number, the inequality sign reverses.
$\Rightarrow \frac{-3(x+1)}{-3}<\frac{6}{-3}\Rightarrow x+1<-2$

Step 2: Subtract $1$ from both sides of the inequality
$\Rightarrow x+1-1<-2-1$
$\Rightarrow x<-3$
$\therefore$ The maximum value of $x$ is $-2$