$30$ apples are arranged in a mannar such that each row contains exactly $3$ apples. The number of columns required for this arrangement is .

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Solution

Total No. of apples $= 30$ .
Each row contains $3$ apples.
By adding $3$ apples $10$ times we get, $3 + 3 + . . . 10$ times $= 3 \times 10 = 30$ .
Hence total No. of columns $= 10$ .

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30 apples are arranged in a mannar such that each row contains exactly 3 apples. The number of columns required for this arrangement is .

Total No. of apples =30. Each row contains 3 apples. By adding 3 apples 10 times we get, 3+3+...10 times =3×10=30. Hence total No. of columns =10.

$30$ apples are arranged in a mannar such that each row contains exactly $3$ apples. The number of columns required for this arrangement is .

Total No. of apples $= 30$ .
Each row contains $3$ apples.
By adding $3$ apples $10$ times we get, $3 + 3 + . . . 10$ times $= 3 \times 10 = 30$ .
Hence total No. of columns $= 10$ .