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Mole Concept in Balanced Reaction

30 cm3 of a m...

Question

30 cm³ of a mixture of methane and nitrogen was sparked with an excess of oxygen. The volume of carbon dioxide formed was 17 cm³. Find the composition of the mixture.The volume were measured at 20⁰C and 750 mm of Hg.

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Solution

Considering that gases behave idealy, PV= nRT

For the mixture of methane and nitrogen,
No. of moles = $\frac{P V}{R T}$
= $\frac{750 \times 30}{62.3 \times 298}$
= 1.23 moles.

For carbon dioxide,
No. of moles
= $\frac{750 \times 17}{62.3 \times 298}$
= 0.69 moles.

And,
CH₄ + 2O₂ $\to$ CO₂ + 2H₂O

1 mole of methane gives 1 mole of carbon dioxide

therefore,
0.69 moles of carbon dioxide is given by 0.69 moles of methane.

No. of moles of nitrogen = 1.23 - 0.69
= 0.59 moles

Composition of mixture is methane by nitrogen is 0.69 : 0.59

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