$30 g$ of Magnesium and $30 g$ of oxygen are reacted, then the residual mixture contains:

50 g

of Magnesium oxide and

10 g

of oxygen

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40 g

of Magnesium oxide and

20 g

of oxygen

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45 g

of Magnesium oxide and

15 g

of oxygen

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50 g

of Magnesium only

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Solution

The correct option is C $50 g$ of Magnesium oxide and $10 g$ of oxygen
$2 M g + O_{2} \to 2 M g O$
According to the above reaction,
$28.6 g (2 m o l e) M g$ combine with $32 g (1 m o l e)$ of $O_{2}$ to give $80.6 g (2 m o l e)$ of MgO.
thus,
$30 g M g$ will combine with $20 g$ of $O_{2}$ to produce $50 g M g O$ and $10 g$ $O_{2}$ will remain unreactive.

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