Question

$30$ persons can reap a field in $17$ days.How many more persons should be engaged to reap the same field in $10$ days?

Answer 1

Given that,

Let number of men’s $\left(M_1\right)=30$

Number of days=$\left(D_1\right)=17$

Again Here, the work done is same field for 10 days

Then, number of men’s$\left(M_2\right)=?$

Number of days$\left(D_2\right)=10$

Now, we know that,

$M_1\times D_1=M_2\times D_2$

$30\times 17=M_2\times 10$

$\Rightarrow M_2=\frac{30\times 17}{10}$

$\Rightarrow M_2=3\times 17$

$\Rightarrow M_2=51$

Hence, $51$ more persons should be engaged to reap the same field in $10$ days.