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Sum of Probabilities

30. Three boy...

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30. Three boys and two girls stand in a queue. The probability that the number of boys ahead of every girl is atleast one more than the number of girls ahead of her, is

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Q. Three boys and two girls stand in a queue. The probability, that the number of boys ahead of every girl is at least one more than the number of girls ahead of her, is

n

be the number of ways in which

5

5

girls can stand in a queue in such a way that all the girls stand consecutively in the queue. Let

m

be the number of ways in which

5

5

girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue. Then the value of

\frac{m}{n}

Three boys and four girls stand in queue for an interview. The probability that they stand in alternate positions is:

Q. Let n be the number of ways in which

5

5

girls an stand in a queue in such a way that all the girls stand consecutively in the queue. Let m be the number of ways in which

5

5

girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue.Then the value of

\frac{m}{n}

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