Question

300 gm of 25% w/w solution of solute A is mixed with 400 gm of 40 (w/w) solution of another solute B. What is the w/w percentage of new mixture.

• A. 10.71% in A
• B. 35% in B
• C. 25% in A
• D. 40% in B

Answer 1

Answer: (A)

10.71% in A

A : 300 g of 25% w/w
B : 400 g of 40% w/w
$w/w\%ofA=\frac{25\%of300}{300+400}=\frac{75}{700}\times 100=10.71\%$
$w/w\%ofB=\frac{40\%of400}{300+400}\times 100=22.85\%$