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Question

300 ml 0.1 M HCl and 200 ml of 0.03 M H2SO4 are mixed. Calculate the normality of the resulting mixture.

A
0.084 N
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B
0.84 N
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C
2.04 N
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D
2.84 N
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Solution

The correct option is A 0.084 N
For HCl
V1=300 ml
N1=M×Basicity
=0.1×1=0.1
For H2SO4
V2=200 ml
N2=M×Basicity
=0.03×2=0.06
Normality of the mixture,
N=V1N1+V2N2V1+V2
N=300×0.1+200×0.06500
N=30+12500=0.084 N

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