300 mL ofgold sol is mixed with 30 mL of 10% NaCl solution. The mass of Haemoglobin in mgrequired to protect the gold sol from coagulation is (gold number of Haemoglobin is 0.03)

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Gold number of haemoglobin is $0.03$ . Hence, $100 m l$ of gold sol will require haemoglobin so that gold is not coagulated by $10 m L$ of $10 % N a C l$ solution:

Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin in what quantity so that gold is not coagulated by 10ml 10% NaCl solution

Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin in what quantity so that gold is not coagulated by 10ml 10% NaCl solution.

Q. The gold number of haemoglobin is 0.03. 100mL of gold sol will require how much haemoglobin so that gold is not coagulated by 10mL of 10% NaCl solution?

Q. The coagulation of

100

mL of a colloidal sol of gold is completely prevented by addition of

0.03

g of haemoglobin to it before adding

1

mL of

10 %

N a C l

solution. Calculate the gold number of haemoglobin.

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