Question

300 mmol of perfect gas occupies 13 L at 320 K. Calculate the work done in joules when the gas undergoes isothermal reversible expansion to 16 L.

Answer 1

Given that,

$V_2=16L$

$V_1=13L$

$n=300mmol=0.3mol$

For a isothermal and reversible process
$W_{max}=-2.303\times n\times R\times T\times log\frac{V_2}{V_1}$
$=-2.303\times 0.30\times 8.314\times 320\times lo{g}_{10}\frac{16}{13}$
$=-165.8J$