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Internal Energy

3000 J of hea...

Question

$3000 J$ of heat is given to a gas at a constant pressure of $P = (2 \times 10^{5} N / m^{2})$ .
If its volume increases by 10 litres during the process, find the change in the internal energy of the gas.

1600 J

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3000 J

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2500 J

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1000 J

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Solution

The correct option is D $1000 J$
Given:
$q = 3000 J$
$P = 2 \times 10^{5} N / m^{2}$
$△ V = 10 \times 10^{- 3} m^{3}$
So, the work done is given as,
$w = - P △ V = - (2 \times 10^{5} N / m^{2}) (10 \times 10^{- 3} m^{3}) = - 2 \times 10^{3} J$

From the first law of thermodynamics,
$△ U = q + w = 3000 - 2000 = 1000 J$

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Internal Energy

Standard XII Chemistry

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3000 J of heat is given to a gas at a constant pressure of P =(2×105 N/m2). If its volume increases by 10 litres during the process, find the change in the internal energy of the gas.

The correct option is D 1000 JGiven: q=3000 J P =2×105 N/m2 △ V=10×10−3m3 So, the work done is given as, w=−P △ V=−(2×105 N/m2)(10×10−3m3)=−2×103 J From the first law of thermodynamics, △U=q+w=3000−2000=1000 J

$3000 J$ of heat is given to a gas at a constant pressure of $P = (2 \times 10^{5} N / m^{2})$ .
If its volume increases by 10 litres during the process, find the change in the internal energy of the gas.