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Momentum

300J of work ...

Question

$300 J$ of work done in sliding a $2 k g$ block up an inclined plane of height $10 m$ . Taking $g = 10 m / s^{2}$ , work done against friction is:

200 J

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100 J

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Zero

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1000 J

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Solution

The correct option is B $100 J$
Apply work energy theorem
$w_{e x t e r n a l} + w_{m g} + w_{f r i c t i o n} = k f_{z} = 0 300 - 20 \times 10 + w_{f} = 0 w_{f} = 100 J W o r k d o n e a g a i n s t f r i c t i o n i s 100 J$

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