$300 J$ of work is done in sliding a $42 k g$ block up an inclined plane of height $10 m$ . The work done against friction is:-
(take $g - 10 m / s^{2}$ )

Zero

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100 J

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200 J

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300 J

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Solution

The correct option is B $100 J$
Net work = Work against friction + Work done by gravity
That is,
$300 = W_{f} + 2 \times g \times 10$
$W_{f} = 100 J$

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