Question

$30th$ term of the A.P. : $10,7,4,...,$ is

• A. $97$
• B. $77$
• C. $-77$
• D. $-87$

Answer 1

Answer: (C)

$-77$

$\begin{array}{c}firstterma=10\\ commondifferenced=7-10=-3\\ a_n=a+\left(n-1\right)d\\ a_{30}=10+\left(30-1\right)\times -3\\ a_{3=}=10+29\times -3\\ a_{30}=10-87\\ a_{30}=-77\end{array}$