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Intensity Amplitude Relationship

31. Distance ...

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31. Distance between the slits, in YDSE, shown in figure is d=20?, where ? is the wavelength of light used. Find the angle ? ,where :- 1. Central maxima (where path difference is zero) is obtained. 2. third order maxima is obtained.

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Assertion:

In the figure shown, zero order maxima will lie above point

O

Reason:

Zero order maxima normally means a point where path difference is zero.

Q. In YDSE experiment D is distance of screen from slit, d is seperation between slits and

λ

is wavelength of light used. If distance of nearest point to the central maxima where intensity is same as that due to single slit is

\frac{n D λ}{m d}

Q. In YDSE, if bichromatic light having wavelength

λ_{1}

λ_{2}

is used, then the maxima due to both lights will overlap at a distance of ...... from the central maxima. Take separation between slits as

d

and distance between screen and slits as

D

. Most appropriate option.. for the blank space is :

Q. In the Young's double slit experiment two light beams of wavelengths

λ = 6000 A^{o}

λ = 4800 A^{o}

are used. The distance between two slits is

2.5 m m

. The distance between slits and the screen is

1.5 m

. The distance between the central maxima obtained with two beams will be

Q. If in Young's double slit experiment, the distance between two slits is twice the wavelength of light used. If distance between slits and screen is

D

then distance of first maxima from central maxima is -

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