$32^{1 / 5}$ is equal to ___.

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Solution

We've,
$32^{\frac{1}{5}}$
$= (2^{5})^{\frac{1}{5}}$
$= 2$ .

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Similar questions

i = \sqrt{- 1} .

\frac{{(- 1 + i \sqrt{3})}^{21}}{(1 - i)^{24}} + \frac{{(1 + i \sqrt{3})}^{21}}{(1 + i)^{24}} = k,

n = [| k |]

| k | .

n + 5 \sum j = 0 (j + 5)^{2} - n + 5 \sum j = 0 (j + 5)

32^{1 / 5}

32^{\frac{1}{5}}

32^{1 / 5}

32^{\frac{1}{5}}

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