32 labourers can finish a piece of work in 84 days. How many labourers will finish the same piece of work in 48 days?

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Solution

It is given that 32 workers can complete a work in 84 days.

We have to find how many workers are required to complete the work in 48 days.

W₁ = 32, D₁ = 84, D₂ = 48, W₂ =?

The work done by 32 workers in 84 days and by W₂ in 48 days will be equal.

Therefore,

W₁ × D₁ = W₂ × D₂

Substituting the given values, we get

32 × 84 = W₂ × 48

W₂ = $\frac{2688}{48}$ 

W₂ = 56

Therefore, 56 workers will complete the same work in 48 days.

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32 labourers can finish a piece of work in 84 days. How many labourers will finish the same piece of work in 48 days?​

32 labourers can finish a piece of work in 84 days. How many labourers will finish the same piece of work in 48 days?