32P beta decays to 32S- find the the sum of the energy of the antinewtrino and the kinetic energy of the - particle neglect the recoil of the daughter nucleus -Atomic mass of 32P - 31-974 u and that pf 32S - 31-972 u

P^32→ S^32 + _0 V̅^0 + _1 β^0 energy of antineutrino and β particle #160; = ( 31.974 31.972 )u = 0.002 u = 0.002 × 931 = 1.862 MeV = 1.86MeV ...

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Standard XII

Chemistry

Difference between Internal Energy and Enthalpy

32P beta deca...

Question

$^{32} P$ beta decays to $^{32} S$ . find the the sum of the energy of the antinewtrino and the kinetic energy of the $β$ particle neglect the recoil of the daughter nucleus .Atomic mass of $^{32} P = 31.974 u$ and that $p f^{32} S = 31.972 u$

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Solution

$P^{32} \to S^{32} +_{0} {¯ V}^{0} +_{1} β^{0}$
energy of antineutrino and $β$ particle
$= (31.974 - 31.972) u = 0.002 u = 0.002 \times 931 = 1.862 M e V = 1.86 M e V$

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32P beta decays to 32S. find the the sum of the energy of the antinewtrino and the kinetic energy of the β particle neglect the recoil of the daughter nucleus .Atomic mass of 32P=31.974u and that pf32S=31.972u

P32→S32+0¯V0+1β0energy of antineutrino and β particle =(31.974−31.972)u=0.002u=0.002×931=1.862MeV=1.86MeV

$^{32} P$ beta decays to $^{32} S$ . find the the sum of the energy of the antinewtrino and the kinetic energy of the $β$ particle neglect the recoil of the daughter nucleus .Atomic mass of $^{32} P = 31.974 u$ and that $p f^{32} S = 31.972 u$

$P^{32} \to S^{32} +_{0} {¯ V}^{0} +_{1} β^{0}$
energy of antineutrino and $β$ particle
$= (31.974 - 31.972) u = 0.002 u = 0.002 \times 931 = 1.862 M e V = 1.86 M e V$