wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

32n+7 is divisible by 8 for all n ∈ N.

Open in App
Solution

Let P(n) be the given statement.
Now,
P(n): 32n+7 is divisible by 8 for all nN.Step 1:P(1)= 32+7=9+7=16 It is divisible by 8.Step 2: Let P(m) be true.Then, 32m+7 is divisible by 8.Thus, 32m+7=8λ for some λN. ...(1)We need to show that P(m+1) is true whenever P(m) is true.Now,P(m+1) =32m+2+7 =32m.9 +7 =(8λ-7).9+7 From (1) =72λ-63+7 =72λ-56 =8(9λ-7) It is a multiple of 8.Thus, P(m+1) is divisible by 8.By the principle of mathematical induction, P(n) is true for all nN.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Playing with 2 - Digit and 3 - Digit Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon