Question

# $\frac{33}{-55}$ in standard form is:

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Solution

## A number is in standard form if the denominator is positive and both the numerator and denominator are co-prime.$\frac{33}{-55}=\frac{-33}{55}$ (Making denominator positive)$\frac{-\overline{)33}}{\overline{)55}}=\frac{-3}{5}$ (Cancelling common factor $11$)Hence, $\frac{33}{-55}$ in standard form is $\frac{-3}{5}$.

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