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Newton's Second Law

33.A block of...

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33.A block of mass m =2kg is resting on the rough inclined plane of inclination 30degree. The coefficient of friction between the block and the plane is 0.5.What minimum force F should be applied perpendicular to the plane on the block, so that block does not slip on the plane

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Q. A block of mass

m = 2 k g

is resting on a rough inclined plane of inclination

30^{o}

as shown in figure. The coefficient of friction between the block and the plane is

μ = 0.5

. What minimum force

F

should be applied perpendicular to the plane on the block, so that block does not slip on the plane.?

(g = 10 m / s^{2})

Q. A block of mass

m = 2 kg

is resting on a rough inclined plane of inclination

30^{\circ}

as shown in figure. The coefficient of friction between the block and the plane is

μ = 0.5

. What minimum force

F

should be applied on the block as shown in figure, so that the block does not slip on the plane?(

g = 10 {ms}^{- 2})

Q. A block of mass

m = 2 kg

is resting on a rough inclined plane of inclination

30^{\circ}

as shown in figure. The coefficient of friction between the block and the plane is

μ = 0.5

. What minimum force

F

should be applied on the block as shown in figure, so that the block does not slip on the plane?(

g = 10 {ms}^{- 2})

Q. A block of mass

m

is kept on a rough inclined plane of inclination

θ

. Coefficient of friction between the block and the plane is

μ

F

parallel to the inclined plane should be applied on the block so that is just begins to slide up the plane? Given,

μ < cot θ

Q. A block of mass

10 kg

is kept on a rough inclined plane of inclination

45^{\circ}

3 N

is applied on the block down the incline. The coefficient of static friction between the plane and the block is

0.6

. What should be the minimum value of force

F

, such that the block does not move downward? (Take

g = 10 {ms}^{- 2}

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