33. solve the equation, 2(sinx +siny)-2cos(x-y)=3 for smallest positive value of x and y

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The smallest positive values of x and y that satisfy 2(sinx + sin y) - 2 cos (x - y) = 3 is

2 (s i n x + s i n y) - 2 c o s (x - y) = 3

(- π \leq x \leq π)

2 (cos x + cos 2 x) + sin 2 x (1 + 2 cos x) = 2 sin x

s i n x + s i n y = 2 s i n \frac{x + y}{2} c o s \frac{x - y}{2}

\frac{s i n x + s i n 3 x}{c o s x + c o s 3 x} = t a n 2 x

x, (- π \leq x \leq π)

2 (c o s x + c o s 2 x) + s i n 2 x (1 + 2 c o s x) = 2 s i n x

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