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Linear Combination of Atomic Orbitals

34.Calculate ...

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34.Calculate the %p character in the orbital occupied by the lone pairs in water molecule. [Given: angle HOH = 104.5^° ; cos 104.5^° = -0.25] 1)80% 2)20% 3)70% 4)75%

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Q. Calculate the % p-character in the orbital occupied by the lone pairs in water molecules :
[Given :

∠ H O H

{104.5}^{\circ}

(104.5) = - 0.25

]

Q. Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The H–O–H bond angle in water molecule is

{104.5}^{o}

.
Reason R : The lone pair–lone pair repulsion of electrons is higher than the bond pair-bond pair repulsion.

Q. The resultant dipole moment of water is 1.85 D, Calculate the bond moment of

O H

bond (in D), bond angle in water molecule is

104^{o}

104^{o}

= -0.25 (Ignore the dipole moment due to lone pair)

Q. In a water molecule, the bond angle of

{104.5}^{o}

around oxygen is accounted due to:

Q. Which of the following accounts for the bond angle of

{104.5}^{o}

in water molecules?

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