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Direct Combination

34. Calculate...

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34. Calculate the volume of HCL (strength 73 gram HCL per litre ) required to neutralize the Sodium Hydroxide formed by action of water on 0.46g of sodium- 1. 15 ml 2. 45ml 3. 50ml 4. 10ml

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Q. The amount of volume (in ml) of a solution of hydrochloric acid containing

73

g of acid per litre that would be required for the exact neutralization of sodium hydroxide obtained by allowing

0.46

g of metalic sodium to act upon water is :

(C l = 35.5, N a = 23.0, O = 16)

Q. What volume in litres of a solution of hydrochloric acid containing

73

g of acid per litre would be sufficient for the exact neutralization of sodium hydroxide obtained by allowing

0. 46

g of metallic sodium to act upon water?

What weight of sodium hydroxide is required to neutralize 100ml of 0.1N HCl

x

mL of a solution of hydrochloric acid containing

73

g acid per litre would suffice for the exact neutralisation of sodium hydroxide obtained by allowing

0.46

g of metallic sodium to act upon water, then find the value of

x

.

Q. 10 mL of a 1 M solution of sodium hydroxide is pipetted into a 100 mL standard flask and made upto the mark. 10 mL of this solution requires 20 mL of HCl for complete neutralization. Calculate the molarity of HCl solution.

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