Question

$34$ g of $H_2{O}_2$ is present in $1120$ mL of solution. This solution is called:

• A. $10$ vol solution
• B. $20$ vol solution
• C. $34$ vol solution
• D. $32$ vol solution

Answer 1

The correct option is A $10$ vol solution

$N=\frac{W\times 1000}{Ew\times V_{mL}}$, where $W$ is the weight in grams, $Ew$ is the equivalent weight and $V_{mL}$ is the volume in mL.

$N=\frac{34\times 1000}{17\times 1120}=\frac{200}{112}$

$1N$ of $H_2{O}_2=5.6$ volume strength

$\frac{200}{112}N$ of $H_2{O}_2=5.6\times \frac{200}{112}=10V$